The Street railway journal (1902) (14575033970)

Identifier: streetrailwayjo201902newy (find matches)
Title: The Street railway journal
Year: 1884 (1880s)
Authors:
Subjects: Street-railroads Electric railroads Transportation
Publisher: New York : McGraw Pub. Co.
Contributing Library: Smithsonian Libraries
Digitizing Sponsor: Smithsonian Libraries



Text Appearing Before Image:
signal to time of full application of brake-shoe would be:0.16.T (S ) 1.467 T = d (distance in feet) (1) December 27, 1902.) STREET RAILWAY JOURNAL. I017 where S = speed at brake signal in miles pe- hour, T = time from brake signal to application of brake shoes,and 1.467 = number of feet per second corresponding to 1 mileper hour. S being the speed at brake signal, and o. 16 miles pe?hour per second the retardation due to friction and windage be-tween brake signal and application of brakes, the total retardationin T seconds will be 0.16 T, and the speed of car at the end of theinterval of T seconds, i. e., at the time of application of the brakeswill be (S — 0.16 T) miles per hour. Letting d = distance from application of brake-shoes to stop (o.i6T\ 1.467S \ 1.467 T+ (S— 0.16 T)2 = D (4)2 J 2 R Equation (4) gives the distance from brake signal to stop interms of S, T and R. Expanding the expressions and collectingthe coefficients of S and S2 we get LS2+MS + N = D0-733 where L = R
Text Appearing After Image:
and T1 = time in seconds from application of brake shoes to stop,we have 1 — (S — 0.16 T) 1.467 X T1 = d1 (2) 2 But if R = rate of retardation in miles per hour per second afterbrakes are set, the time T1 may be expressed as follows: S —0.16 T T^— R and substituting this value in equation (2) we have:(S —0.16 T) 1.467 S —0.16T X = <F 2 R or 1.467 (S-0.16T)2 = d* (3) 2R Let D = total distance from brake signal to stop. Then d -f- d1= D and substituting from equations (1) and (3) we have: